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so if the complex number is i, in this case
and the result is z=1
Oh I see, and because of this squaring inaccuracy the answers must be checked to see if they work. I recall reading that absolute value can be calculated as ((X)^2)^1/2), although would that make |i| = i
oh and have you seen this thread
It's a pretty clever way to add multiple languages to a game by having the community fill in all the text in their own language.
oh I see what you mean, doesn't that prove that
i got x + x^2 = 2x by multiplying both sides by x
x(sqrt(x) + x) = x(2)
ohh wait thats where I went wrong since sqrt(x) * (x) =/= x
isn't x(x-1) the same as x^2-x?
that would be
x + x^2 = 2x
or am I doing something weird
So if it were valid for sin(x) = 0 then the result would need to include that it works for all cases where x=/=0
Thanks! That was only one remaining that I had trouble with as many of them are just the same technique .
yes I was trying to convert it all into parenthesis but I messed up there , i'm trying to verify the identity
Oh thanks I have a quiz we were allowed to take home because no one finished in class
also I can't figure out where I went wrong here
((1+cos(x))/sin(x)) + ((sin(x))/1+cos(x)) = 2csc(x)
(1+cos(x))^2+sin^2(x) = 2 + 2cos(x)
1+cos(x) + cos^2(x) + 1 +sin^2(x) = 2+2 cos(x)
clean it up a bit
cos(x) + cos^2(x)+sin^2(x) = 2 cos(x)
sin^2(x) + cos(x)(cos(x)+1) = 2cos(x)
from here I can't find any identity that seems to fix it o.O
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