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For all those Algebra folk trying to complete squares, here you go: Image Form Text Form a(x - (b/(2a)))^{2} + (-a(b/(2a))^{2}+d) = 0 To know what variables to put in, look at this format: ax^{2} + bx + d = 0 Why d and not c? Well, I consider c as a perfectly squared number of (x + y)^{2}, or y^{2}. D, in this case, is not y^{2}. Let me show you an example. ...

Updated 6th November 2014 at 03:55 PM by Zinx10

Okay, so I have to explain this: x + √(x) = 6 It is highly obvious that "x = 4," but is there any way to explain it algebraically (most likely through the use of factoring)? If so, could someone give the steps towards how to do it? Also, for proof that x = 4: 4 + √(4) = 6 4 + 2 = 6 I just need to know how to do it through variables: x + √(x) = 6 Not sure if this will help, but: √(x)(√(x) + 1) = x^{1/2} ...

Okay, I brought it up before, and I will bring it up again: is Final Fantasy XIII really that bad? From what I played (5-6 hours), the game was very fun. Please explain to me what your thoughts on it were. Also, please don't include spoilers for I will finish it so I can give my true opinion on it.

My girlfriend is as real as √(-1).

GIVEN: z = u(w)(m)(√((x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}) - (S_{avg} / 60000)(N) 100 = L_{avg}(N) - w((z) / 60) *I ATTEMPT TO SOLVE FOR N* 100 = L_{avg}(N) - w((u(w)(m)(√((x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}) - (S_{avg} / 60000)(N)) / 60) 100 = ((60L_{avg}(N)) / (60)) - w((u(w)(m)(√((x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}) - (S_{avg} / 60000)(N)) / 60) 6000 = L_{avg}(N) - w(u(w)(m)(√((x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}) - (S_{avg} / 60000)(N)) 6000 = L_{avg}(N) - wu(w^{2})(wm)(w√((x_{2} - x_{1}) ...

Updated 13th October 2014 at 08:00 AM by Zinx10