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Okay, so I have to explain this: x + √(x) = 6 It is highly obvious that "x = 4," but is there any way to explain it algebraically (most likely through the use of factoring)? If so, could someone give the steps towards how to do it? Also, for proof that x = 4: 4 + √(4) = 6 4 + 2 = 6 I just need to know how to do it through variables: x + √(x) = 6 Not sure if this will help, but: √(x)(√(x) + 1) = x^{1/2} ...

Okay, I brought it up before, and I will bring it up again: is Final Fantasy XIII really that bad? From what I played (5-6 hours), the game was very fun. Please explain to me what your thoughts on it were. Also, please don't include spoilers for I will finish it so I can give my true opinion on it.

My girlfriend is as real as √(-1).

GIVEN: z = u(w)(m)(√((x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}) - (S_{avg} / 60000)(N) 100 = L_{avg}(N) - w((z) / 60) *I ATTEMPT TO SOLVE FOR N* 100 = L_{avg}(N) - w((u(w)(m)(√((x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}) - (S_{avg} / 60000)(N)) / 60) 100 = ((60L_{avg}(N)) / (60)) - w((u(w)(m)(√((x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}) - (S_{avg} / 60000)(N)) / 60) 6000 = L_{avg}(N) - w(u(w)(m)(√((x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}) - (S_{avg} / 60000)(N)) 6000 = L_{avg}(N) - wu(w^{2})(wm)(w√((x_{2} - x_{1}) ...

Updated 13th October 2014 at 08:00 AM by Zinx10

In your head, what is the answer to this? x = sqrt(-144) = (-144)^{0.5} x = ? I know it, but dost thou? Odds are people above Algebra II will get it in no problem. This is mainly a test for people around Algebra II level (assuming these values count to you).